document.write( "Question 30245: $\"myspace\"$
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\n" ); document.write( "\n" ); document.write( "Can you please tell me the answer to this?\r
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\n" ); document.write( "\n" ); document.write( " $\"%28x%29%2F%28j-k%29-%28x%29%2F%28j%2Bk%29=1\"$ \r
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Algebra.Com's Answer #16998 by sdmmadam@yahoo.com(530) $\"\"$ $\"About$

You can put this solution on YOUR website!
x/(j-k) - x/(j+k) = 1 ----(1)
\n" ); document.write( "Multiplying by (j-k)(j+k) which is the lcm of (j-k)and (j+k)
\n" ); document.write( "x(j+k)-x(j-k) = (j-k)(j+k)
\n" ); document.write( "x[j+k-j+k] = j^2-k^2 (taking x out on the LHS and applying formula on the RHS)
\n" ); document.write( "x(2k) =j^2-k^2
\n" ); document.write( "x = (j^2-k^2)/2k
\n" ); document.write( "Answer: x = (j^2-k^2)/2k
\n" ); document.write( "Verification: x= (j^2-k^2)/2k in (1)
\n" ); document.write( "LHS = (j^2-k^2)/2k (j-k) -(j^2-k^2)/2k (j+k)
\n" ); document.write( "=(j+k)/2k-(j-k)/2k
\n" ); document.write( "=[(j+k)-(j-k)]/2k
\n" ); document.write( "=(j+k-j+k)/2k
\n" ); document.write( "=(2k)/2k= 1 = RHS
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