document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=30306>Question 30306</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am asked to simply this problem:<BR>\n" );
document.write( " 6^3a+2 multiplied by 6^2-2a over 6^a+5<BR>\n" );
document.write( "(6 to the 3a+2 power multiplied by 6 to the 2nd power minus 2a power over 6 to the A power plus 5th power<BR>\n" );
document.write( "6^3a+2 multiplied by 6^2-2a<BR>\n" );
document.write( "---------------------------<BR>\n" );
document.write( "           6^a+5<BR>\n" );
document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #16989 by </B><A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><B>sdmmadam@yahoo.com(530)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=16989\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6^3a+2 multiplied by 6^2-2a<BR>\n" );
document.write( "---------------------------<BR>\n" );
document.write( "           6^a+5\r<BR>\n" );
document.write( "\n" );
document.write( "=[(6)^(3a+2)]X[(6)^(2-2a)]X[1/(6)^(a+5)]     (using (ab)/c = (ab)X(1/c) )<BR>\n" );
document.write( "={(6)^[(3a+2)+(2-2a)]}X[1/(6)^(a+5)]   <BR>\n" );
document.write( "(when quantities of the same base are multiplied <BR>\n" );
document.write( "write the base and add the powers)<BR>\n" );
document.write( "=(6)^[3a-2a+2+2]X(6)^[-(a+5)]    ( Using the rule (1/a^m) = (a)^(-m))<BR>\n" );
document.write( "=(6)^(a+4) X (6)[-(a+5)]    <BR>\n" );
document.write( "=(6)^[(a+4)-(a+5)] <BR>\n" );
document.write( "(when quantities of the same base are multiplied <BR>\n" );
document.write( "write the base and add the powers)<BR>\n" );
document.write( "=(6)^(a+4-a-5)<BR>\n" );
document.write( "=(6)^(4-5)<BR>\n" );
document.write( "=(6)^(-1)<BR>\n" );
document.write( "=1/(6)^1<BR>\n" );
document.write( "=1/6<BR>\n" );
document.write( "    \r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );