document.write( "Question 228977: the alan company bout 80 tickets for a jazz conert. after giving away 20 tickets to customers, the company sold the rest to emplyees at half of the purchase price. if the company absorbed a $1000 loss on all tickets, how much did an emplyee pay for a ticket? \n" ); document.write( "

Algebra.Com's Answer #169871 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"p\"$ = purchase price of a ticket
\n" ); document.write( "Amount taken in for sales to employees =
\n" ); document.write( " $\"60%2A%28p%2F2%29\"$
\n" ); document.write( "This amount is $1000 less than the price of 80 tickets which =
\n" ); document.write( " $\"80p\"$
\n" ); document.write( " $\"60%2A%28p%2F2%29+=+80p+-+1000\"$
\n" ); document.write( " $\"60p+=+160p+-+2000\"$
\n" ); document.write( " $\"100p+=+2000\"$
\n" ); document.write( " $\"p+=+20\"$
\n" ); document.write( "An employee paid $\"p%2F2\"$ per ticket
\n" ); document.write( " $\"p%2F2+=+10\"$
\n" ); document.write( "Employees played $10 for a ticket
\n" ); document.write( "check:
\n" ); document.write( " $\"60%2A%28p%2F2%29+=+80p+-+1000\"$
\n" ); document.write( " $\"60%2A10+=+80%2A20+-+1000\"$
\n" ); document.write( " $\"600+=+1600+-+1000\"$
\n" ); document.write( " $\"600+=+600\"$
\n" ); document.write( "OK \n" ); document.write( "

\n" );