document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=228927>Question 228927</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the length of the shorter leg of a right triangle if the longer leg is 6 feet more than the shorter leg and the hypothenuse is 6 feet less than twice the shorter leg. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #169834 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=169834\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let a=shorter leg, b=longer leg, c=hypotenuse<BR>\n" );
document.write( "b=a+6<BR>\n" );
document.write( "c=2a-6<BR>\n" );
document.write( "a^2+b^2=c^2<BR>\n" );
document.write( "a^2+(a+6)^2=(2a-6)^2<BR>\n" );
document.write( "a^2+a^2+12a+36=4a^2-24a+36<BR>\n" );
document.write( "2a^2+12a=4a^2-24a subtract 36 from each side.<BR>\n" );
document.write( "a^2+6a=2a^2-12a divide each side by 2.<BR>\n" );
document.write( "a^2-18a=0<BR>\n" );
document.write( "a(a-18)=0 factor<BR>\n" );
document.write( "a=0, a=18<BR>\n" );
document.write( "18' shortest leg's length.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );