document.write( "Question 228692: solve sqrt x + 5 = sqrt x^2 - 15 \n" ); document.write( "
Algebra.Com's Answer #169709 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
\"sqrt%28x%2B5%29=sqrt%28x%5E2-15%29\"\r
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\n" ); document.write( "\n" ); document.write( "Square both sides:
\n" ); document.write( "\"x%2B5=x%5E2+-15\"\r
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\n" ); document.write( "\n" ); document.write( "It's quadratic, so set it equal to zero by subtracting x +5 from each side:
\n" ); document.write( "\"0=x%5E2+-x+-15-5\"
\n" ); document.write( "\"0=x%5E2-x-20\"
\n" ); document.write( "\"0=%28x-5%29%28x%2B4%29+\"\r
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\n" ); document.write( "\n" ); document.write( "There are two solutions:
\n" ); document.write( "x= 5 or x=-4\r
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\n" ); document.write( "\n" ); document.write( "You HAVE TO CHECK the answers:\r
\n" ); document.write( "\n" ); document.write( "First solution: x=5
\n" ); document.write( "\"sqrt%285%2B5%29+=+sqrt%2825-15%29\"
\n" ); document.write( "\"sqrt%2810%29=sqrt%2810%29\"
\n" ); document.write( "It checks!\r
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\n" ); document.write( "\n" ); document.write( "Second solution: x=-4
\n" ); document.write( "\"sqrt%28-4%2B5%29=sqrt%2816-15%29\"
\n" ); document.write( "\"sqrt%281%29=sqrt%281%29\"
\n" ); document.write( "It checks!\r
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\n" ); document.write( "\n" ); document.write( "Both solutions work, x= 5, x=-4.\r
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\n" ); document.write( "\n" ); document.write( "Dr. Robert J. Rapalje, Retired
\n" ); document.write( "Seminole State College of Florida
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