document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=228681>Question 228681</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A group on tour has been drawing crowds of 500 people. It is projected that for every $1 increase in the $12 ticket price the average attendance will decrease by 50. At what price will the nightly receipts be $5600. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #169693 by </B><A HREF=/tutors/aboutme.mpl?userid=user_dude2008><B>user_dude2008(1862)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=user_dude2008><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=169693\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = # of price increases\r<BR>\n" );
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document.write( "revenue = price * number of people<BR>\n" );
document.write( "R = (12+x)(500-50x)<BR>\n" );
document.write( "R = -50 x^2-100x+6000<BR>\n" );
document.write( "5600 = -50 x^2-100x+6000<BR>\n" );
document.write( "0 = -50 x^2-100x+400<BR>\n" );
document.write( "0 = -50(x^2+2x-8)<BR>\n" );
document.write( "0 = -50(x-2)(x+4)<BR>\n" );
document.write( "x = 2 or x = -4\r<BR>\n" );
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document.write( "Answer: price will be 12+2=$14 </SPAN>\n" );
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