document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=228666>Question 228666</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the measure of an angle such that the  difference between the measures of it's supplement and three times it's complement is 10 degre\r<BR>\n" );
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document.write( "how do I write the formula to solve this? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #169684 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=169684\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the angle<BR>\n" );
document.write( "90-x= the complement<BR>\n" );
document.write( "180-x= the supplement\r<BR>\n" );
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document.write( "\"the difference between the measures of its supplement and 3 times its complement is 10\"\r<BR>\n" );
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document.write( "(180-x)-3(90-x)=10\r<BR>\n" );
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document.write( "180-x-270+ 3x=10<BR>\n" );
document.write( "-90 +2x = 10\r<BR>\n" );
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document.write( "Add 90 to each side:<BR>\n" );
document.write( "2x= 100<BR>\n" );
document.write( "x=50 degrees = The angle\r<BR>\n" );
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document.write( "Complement = 90-50=40 degrees<BR>\n" );
document.write( "Supplement = 180-50=130 degrees\r<BR>\n" );
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document.write( "Check:  3 times the complement = 3(40)=120 degrees\r<BR>\n" );
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document.write( "The difference between the supplement and 3 times the complement is 10 degrees, so it checks!\r<BR>\n" );
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document.write( "Dr. Robert J. Rapalje, Retired<BR>\n" );
document.write( "Seminole State College of Florida\r<BR>\n" );
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document.write( " </SPAN>\n" );
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