document.write( "Question 228620: an aircraft uses 1680 gallons of fuel,the left tank used 45%,the right tank used 32.5%.how nuch was used by centre tank? \n" ); document.write( "
Algebra.Com's Answer #169681 by jim_thompson5910(35256)\"\" \"About 
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Assuming that there are only three tanks, this means that the percentages must add to 100%. So let 'x' be the unknown percentage used by the center tank. Now add up the percentages and set them equal to 100 to get: \"45%2B32.5%2Bx=100\". \r
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\n" ); document.write( "\n" ); document.write( "Now solve for 'x' to get \"77.5%2Bx=100\" ---> \"x=22.5\"\r
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\n" ); document.write( "\n" ); document.write( "So the center tank used 22.5% of the fuel. Now just multiply the total amount of fuel (1680) by 0.225 (the decimal representation of 22.5%): 1680*0.225=378\r
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\n" ); document.write( "\n" ); document.write( "So the center tank used 378 gallons of fuel.
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