document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=228673>Question 228673</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is twice its width and its perimeter is 120 cm. Find the dimensions of the rectangle. I know the answer is 40cm x20cm but i need the formula </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #169678 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=169678\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L = 2W and...<BR>\n" );
document.write( "P = 120, so...<BR>\n" );
document.write( "2(L+W) = 120 Substitute L = 2W.<BR>\n" );
document.write( "2((2W)+W) = 120 Divide both sides by 2 and simplify the left side.<BR>\n" );
document.write( "3W = 60 Divide both sides by 3.<BR>\n" );
document.write( "W = 20 and L = 2(20) = 40<BR>\n" );
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