document.write( "Question 228603:
\n" ); document.write( "A chemist has one solution containing a 16% concentration of acid and a second solution containing a 26% concentration of acid. How many milliliters of each should be mixed in order to obtain 30 milliliters of a solution containing an 18% concentration of acid?
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Algebra.Com's Answer #169665 by checkley77(12844)\"\" \"About 
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.26x+.16(30-x)=.18*30
\n" ); document.write( ".26x+4.8-.16x=5.4
\n" ); document.write( ".10x=5.4-4.8
\n" ); document.write( ".10x=.6
\n" ); document.write( "x=.6/.10
\n" ); document.write( "x=6 ml. of the 26% solution is used.
\n" ); document.write( "30-6=24 ml. of the 16% solution is used.
\n" ); document.write( "Proof:
\n" ); document.write( ".26*6+.16*24=5.4
\n" ); document.write( "1.56+3.84=5.4
\n" ); document.write( "5.4=5.4
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