document.write( "Question 228603:
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document.write( "A chemist has one solution containing a 16% concentration of acid and a second solution containing a 26% concentration of acid. How many milliliters of each should be mixed in order to obtain 30 milliliters of a solution containing an 18% concentration of acid? \n" );
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Algebra.Com's Answer #169665 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .26x+.16(30-x)=.18*30 \n" ); document.write( ".26x+4.8-.16x=5.4 \n" ); document.write( ".10x=5.4-4.8 \n" ); document.write( ".10x=.6 \n" ); document.write( "x=.6/.10 \n" ); document.write( "x=6 ml. of the 26% solution is used. \n" ); document.write( "30-6=24 ml. of the 16% solution is used. \n" ); document.write( "Proof: \n" ); document.write( ".26*6+.16*24=5.4 \n" ); document.write( "1.56+3.84=5.4 \n" ); document.write( "5.4=5.4 \n" ); document.write( " |