document.write( "Question 228604:
\n" ); document.write( "A small company had $24,000 to invest. It invested some of the money in a bank that paid 8% annual simple interest. The rest of the money was invested in stocks that paid dividends equivalent to 11% annual simple interest. At the end of 1 year, the combined income from these investments was $2,340. How much was originally invested in stocks?
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Algebra.Com's Answer #169663 by checkley77(12844)\"\" \"About 
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.11x+.08(24,000-x)=2,340
\n" ); document.write( ".11x+1,920-.08x=2,340
\n" ); document.write( ".03x=2,340-1,920
\n" ); document.write( ".03x=420
\n" ); document.write( "x=420/.03
\n" ); document.write( "x=14,000 amount invested @ 11%.
\n" ); document.write( "24,000-14,000=10,000 invested @ 8%.
\n" ); document.write( "Proof:
\n" ); document.write( ".11*14,000+.08*10,000=2,340
\n" ); document.write( "1,540+800=2,340
\n" ); document.write( "2,340=2,340
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