document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=228574>Question 228574</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the digits of a two-digit number is 14. If the digits are reversed, the result exceeds the original number by 18. Find the original number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #169652 by </B><A HREF=/tutors/aboutme.mpl?userid=Wolvstein><B>Wolvstein(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Wolvstein><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=169652\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Okay, this you can solve using the hit and trial method. <BR>\n" );
document.write( "Now, since 14 is a sum of two digits and we have to reverse them in order to make a number, none of the digits can exceed 10. Which leaves us with <BR>\n" );
document.write( "a) 5 and 9<BR>\n" );
document.write( "b) 6 and 8<BR>\n" );
document.write( "c) 7 and 7.<BR>\n" );
document.write( "All of these add up to 14.<BR>\n" );
document.write( " The answer is b). 68-86= -18 (The negative sign denotes that if the digits are reversed, the result exceeds the original number by 18)\r<BR>\n" );
document.write( "\n" );
document.write( "The original number is 68. </SPAN>\n" );
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