document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=228532>Question 228532</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the width of a rectangle is 4 inches less than than its length. The perimeter is 112 inches. Find the length and the width of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #169632 by </B><A HREF=/tutors/aboutme.mpl?userid=mangeshpjoshi><B>mangeshpjoshi(15)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mangeshpjoshi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mangeshpjoshi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=169632\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> formula for perimeter of rectangle<BR>\n" );
document.write( "= 2(length + breadth)<BR>\n" );
document.write( "let L= length so as per given instruction Breadth =B =L-4<BR>\n" );
document.write( " so P= 112=2(L+L-4)<BR>\n" );
document.write( "112/2= 2L-4<BR>\n" );
document.write( "56=2L-4<BR>\n" );
document.write( "60= 2L<BR>\n" );
document.write( "L= 30<BR>\n" );
document.write( "B= 30-4=26<BR>\n" );
document.write( "thanks<BR>\n" );
document.write( "faithfully<BR>\n" );
document.write( "mangesh joshi </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );