document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=228501>Question 228501</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3. a hiker walks 6 miles into a forest on a trail that is mainly up hill. she walks down at a rate of 1.2 times as fast as she walked up. if the return trip takes 40 minutes (2/3 hour) less than the hike up, at what rate did the hiker walk up the hill?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #169619 by </B><A HREF=/tutors/aboutme.mpl?userid=drj><B>drj(1380)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drj><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=drj><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=169619\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3. A hiker walks 6 miles into a forest on a trail that is mainly up hill. She walks down at a rate of 1.2 times as fast as she walked up. If the return trip takes 40 minutes (2/3 hour) less than the hike up, at what rate did the hiker walk up the hill?\r<BR>\n" );
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document.write( "Step 1.  distance = speed * time\r<BR>\n" );
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document.write( "Step 2.  Let x be the speed or rate of the hiker going up the hill.\r<BR>\n" );
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document.write( "Step 3.  Let 1.2x be the speed or ate of the hiker going down the hill since she walks down at a rate 1.2 time as fast as she walked up.\r<BR>\n" );
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document.write( "Step 4.  Then <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6=1.2x%2A2%2F3 ALIGN=MIDDLE  ALT=\"6=1.2x%2A2%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > since the distance is 6 miles and the time for the return trip is 2/3 hour.\r<BR>\n" );
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document.write( "Step 5.  Solve for <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x ALIGN=MIDDLE  ALT=\"x\"   DISABLED_style= \"max-width:90%; height:auto;\" > in the equation <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6=1.2x%2A2%2F3 ALIGN=MIDDLE  ALT=\"6=1.2x%2A2%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > using the following steps\r<BR>\n" );
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document.write( "Multiply by 3 to get rid of denominator\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6%2A3=1.2x%2A2%7D%7D%0D%0A%0D%0A%0D%0A%7B%7B%7B18=2.4x ALIGN=MIDDLE  ALT=\"6%2A3=1.2x%2A2%7D%7D%0D%0A%0D%0A%0D%0A%7B%7B%7B18=2.4x\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Divide by 2.4 to both sides of the equation\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=18%2F2.4=2.4x%2F2.4 ALIGN=MIDDLE  ALT=\"18%2F2.4=2.4x%2F2.4\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=7.5=x ALIGN=MIDDLE  ALT=\"7.5=x\"   DISABLED_style= \"max-width:90%; height:auto;\" >  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1.2x=9 ALIGN=MIDDLE  ALT=\"1.2x=9\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Then check distance if 6 miles traveling at 9 miles per hour downhill.  9*2/3=6 miles which is a true statement.\r<BR>\n" );
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document.write( "Step 6.  ANSWER:  The hiker traveled at a speed of 7.5 miles per hour going up the hill.\r<BR>\n" );
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document.write( "I hope the above steps were helpful.\r<BR>\n" );
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document.write( "For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.\r<BR>\n" );
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document.write( "Good luck in your studies!\r<BR>\n" );
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document.write( "Respectfully,<BR>\n" );
document.write( "Dr J\r<BR>\n" );
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