document.write( "Question 30287: A jar of nickels and dimes contains $3.30. There are 27 more nickels than dimes. How many of each are there? \n" ); document.write( "
Algebra.Com's Answer #16960 by smoothflyin(6)![]() ![]() ![]() You can put this solution on YOUR website! To solve this first assign variables to your various terms. \r \n" ); document.write( "\n" ); document.write( "Let n=nickels and let d=dimes\r \n" ); document.write( "\n" ); document.write( "We know that Nickels=5 cents and dimes=10 cents so we can then say that\r \n" ); document.write( "\n" ); document.write( "5n+10d=330\r \n" ); document.write( "\n" ); document.write( "(5 cents times the number of nickels (n) plus 10 cents times the number of dimes (d) is equal to our total number of cents. 330 or $3.30)\r \n" ); document.write( "\n" ); document.write( "we then read in our problem that There are 27 more nickels than dimes. \r \n" ); document.write( "\n" ); document.write( "We can express this like so (n=d+27) or the number of nickels is equal to the number of dimes plus 27.\r \n" ); document.write( "\n" ); document.write( "Now that we have a term to work with we can plug n=d+27 back into our original equattion.\r \n" ); document.write( "\n" ); document.write( "5n+10d=330\r \n" ); document.write( "\n" ); document.write( "5(d+27)+10d=330\r \n" ); document.write( "\n" ); document.write( "5d+135+10d=330\r \n" ); document.write( "\n" ); document.write( "Combine like terms\r \n" ); document.write( "\n" ); document.write( "15d+135=330\r \n" ); document.write( "\n" ); document.write( "Bring the \"135\" over the equal sign, its sign reverses and so you will subtract it from 330\r \n" ); document.write( "\n" ); document.write( "15d=330-135\r \n" ); document.write( "\n" ); document.write( "combine like terms\r \n" ); document.write( "\n" ); document.write( "15d=195\r \n" ); document.write( "\n" ); document.write( "divide through by 15\r \n" ); document.write( "\n" ); document.write( "d=13\r \n" ); document.write( "\n" ); document.write( "Number of dimes=13 \n" ); document.write( "Number of Nickles=40 \n" ); document.write( " |