document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=228329>Question 228329</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If you were to randomly select 3 movies from a selection of 29 movies, how many different lists of 3 could you have?<BR>\n" );
document.write( "Re-arranging the 3 does NOT make a new list.\r<BR>\n" );
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document.write( "I tried to do 29*28*27 which = 21924 but I think that that includes all the 3 groups that are re-arranged.\r<BR>\n" );
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document.write( "How should I go about solving this problem? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #169555 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=169555\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If you were to randomly select 3 movies from a selection of 29 movies, how many different lists of 3 could you have?<BR>\n" );
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document.write( "You were counting arrangements of three objects.<BR>\n" );
document.write( "You want to count GROUPS of three objects.<BR>\n" );
document.write( "29C3 = 29!/[(29-3)!*3!]<BR>\n" );
document.write( "= (29*28*27)/(1*2*3) = 29*14*9 = 3654<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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