document.write( "Question 228323: Please help!\r
\n" ); document.write( "\n" ); document.write( "If log b < 0, what can you say about b?\r
\n" ); document.write( "\n" ); document.write( "Thanks so much!
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Algebra.Com's Answer #169554 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
Let x = a positive number.\r
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\n" ); document.write( "\n" ); document.write( "Then -x = a negative number.\r
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\n" ); document.write( "\n" ); document.write( "log(b) < 0 implies that log(b) = -x because -x < 0.\r
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\n" ); document.write( "\n" ); document.write( "Now log(b) = -x if and only if 10^(-x) = b.\r
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\n" ); document.write( "\n" ); document.write( "This is by basic definition of logarithms.\r
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\n" ); document.write( "\n" ); document.write( "10^-x is the same as 1/10^x by definition.\r
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\n" ); document.write( "\n" ); document.write( "Since x >= 0 by definition, then the smallest 10^x could be would be 1 because 10^0 = 1. \r
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\n" ); document.write( "\n" ); document.write( "Any other value of x > 0 would result in 10^x being greater than 1.\r
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\n" ); document.write( "\n" ); document.write( "Example:\r
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\n" ); document.write( "\n" ); document.write( "10^0.1 = 1.2589.....\r
\n" ); document.write( "\n" ); document.write( "10^0.00001 = 1.0000023026\r
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\n" ); document.write( "\n" ); document.write( "Bottom Line is the smallest 10^x can be is 1.\r
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\n" ); document.write( "\n" ); document.write( "Now, if 1/10^x = b, this means that the largest b can be is 1 because 1/1 = 1.\r
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\n" ); document.write( "\n" ); document.write( "so, to answer your question:\r
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\n" ); document.write( "\n" ); document.write( "If log(b) < 0, this means that 0 < b < 1\r
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\n" ); document.write( "\n" ); document.write( "Some examples:\r
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\n" ); document.write( "\n" ); document.write( "log(2) = .3...
\n" ); document.write( "log(1) = 0
\n" ); document.write( "log(.9) = -.04...
\n" ); document.write( "log(.5) = -.301...
\n" ); document.write( "log(.1) = -1
\n" ); document.write( "log(0) = Error - can only take log of a number > 0\r
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\n" ); document.write( "\n" ); document.write( "So that's the answer to your question.\r
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\n" ); document.write( "\n" ); document.write( "log(b) < 0 if and only if b is greater than 0 and b is smaller than 1.
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