document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=30291>Question 30291</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the digits of a two-digit number is 15. If the digits are reversed, the new number is 27 less than the original number. Find the original number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #16954 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=16954\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THe original number is 10x+y<BR>\n" );
document.write( "x is the ten digit and y is the  one digit<BR>\n" );
document.write( "Sum:<BR>\n" );
document.write( "x+y=15<BR>\n" );
document.write( "y=15-x (subsitution)\r<BR>\n" );
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document.write( "Digits reversed:<BR>\n" );
document.write( "10y+x --. Now the ones is tens and the tens is ones:<BR>\n" );
document.write( "10y+x=(10x+y)-27<BR>\n" );
document.write( "10(15-x)+x=10x+15-x-27<BR>\n" );
document.write( "150-9x=9x-12<BR>\n" );
document.write( "-18x=-162<BR>\n" );
document.write( "x=9\r<BR>\n" );
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document.write( "y=15-9<BR>\n" );
document.write( "y=6\r<BR>\n" );
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document.write( "<font color = blue>Hence, the 2 digit number is 96. 9-->10 digit and 6-->one digit</font>.<BR>\n" );
document.write( "Paul.<BR>\n" );
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