document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=228315>Question 228315</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A train heads straight east at constant speed at 9am. At noon, a car heads straight east at twice the speed of the train. What time will it be when the car catches up to the train? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #169509 by </B><A HREF=/tutors/aboutme.mpl?userid=JenniferTutors><B>JenniferTutors(83)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JenniferTutors><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JenniferTutors><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=169509\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For this problem I drew a graph to help represent times and distance for each vehicle. <BR>\n" );
document.write( "First, If the train is going 50mph for 3 hours (9-12) that would equal 150 miles reached. If the car is going twice as fast, in this case, 100 then at one o'clock the car would have traveled 100 miles(add100mph); while the train would have traveled 200 miles(add50mph). By 2 o'clock the car would have traveled 200, and the train 250 miles. By 3 o'clock the car would reach 300 miles, and the train as well. So, they both would meet at 3pm.    </SPAN>\n" );
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