document.write( "Question 227994: A chemist needs 130 milliliters of a 28% solution but has only 19% and 58% solutions available. Find how many milliters of each that should be mixed to get the desired solution. \n" ); document.write( "
Algebra.Com's Answer #169502 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A chemist needs 130 milliliters of a 28% solution but has only 19% and 58% solutions available. \n" ); document.write( "Find how many milliliters of each that should be mixed to get the desired solution. \n" ); document.write( ": \n" ); document.write( "Let x = amt of 58% solution \n" ); document.write( "It say's the amt of the resulting mixture is to be 130 ml, therefore \n" ); document.write( "(130-x) = amt of 19% solution \n" ); document.write( ": \n" ); document.write( "A typical mixture equation \n" ); document.write( ": \n" ); document.write( ".58x + .19(130-x) = .28(130) \n" ); document.write( ": \n" ); document.write( ".58x + 24.7 - .19x = 36.4 \n" ); document.write( ": \n" ); document.write( ".58x - .19x = 36.4 - 24.7 \n" ); document.write( ": \n" ); document.write( ".39x = 11.7 \n" ); document.write( "x = \n" ); document.write( "x = 30 ml of 58% solution required \n" ); document.write( "and \n" ); document.write( "130 - 30 = 100 ml of 19% solution \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check solution in original mixture equation \n" ); document.write( ".58(30) + .19(100) = .28(130) \n" ); document.write( "17.4 + 19 = 36.4 \n" ); document.write( " |