document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=228239>Question 228239</A>: <I><SPAN STYLE=\"word-break: break-all;\"> When a card is selected from a standard deck of cards, find the probability of getting an ace followed by an ace without replacement </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #169465 by </B><A HREF=/tutors/aboutme.mpl?userid=drj><B>drj(1380)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drj><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=drj><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=169465\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> When a card is selected from a standard deck of cards, find the probability of getting an ace followed by an ace without replacement\r<BR>\n" );
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document.write( "Step 1.  We note that there are 4 aces in a 52-card deck.\r<BR>\n" );
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document.write( "Step 2.  The probability of an ace in the first card is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=P%28A%29=4%2F52=1%2F13 ALIGN=MIDDLE  ALT=\"P%28A%29=4%2F52=1%2F13\"   DISABLED_style= \"max-width:90%; height:auto;\" > we call this the P(A)\r<BR>\n" );
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document.write( "Step 3.  Since there is no replacement, there are only 3 aces out of the 51 cards since we assume an ace is drawn in the first card.  Therefore, the probability of an ace on the second draw is P(B|A)=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2F51 ALIGN=MIDDLE  ALT=\"3%2F51\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  We call this P(B|A) where the Probability of drawing an Ace on the second draw given that Probability of A occurred or an ace was drawn on the first try.  This is also known as a conditional probability.\r<BR>\n" );
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document.write( "Step 4.  The probability is the product of the probabilities found in Steps 2 and 3.  P(A and B)=P(B|A)P(A) or P(A and B)=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2F51%2A1%2F13=3%2F663 ALIGN=MIDDLE  ALT=\"3%2F51%2A1%2F13=3%2F663\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Step 5.  ANSWER:  The probability of  getting an ace followed by an ace without replacement is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2F663 ALIGN=MIDDLE  ALT=\"3%2F663\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "I hope the above steps were helpful.\r<BR>\n" );
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document.write( "For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.\r<BR>\n" );
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document.write( "Good luck in your studies!\r<BR>\n" );
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document.write( "Respectfully,<BR>\n" );
document.write( "Dr J\r<BR>\n" );
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document.write( " </SPAN>\n" );
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