document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=228207>Question 228207</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 5)Janet drove her car due west for 3 hours while April drove her car due east for 2 hours. Janet drove 20km/hr faster than April. Their total distance driven combined is 400 km.\r<BR>\n" );
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document.write( "a) Complete the following table<BR>\n" );
document.write( "------(km/hr)Distance-----Speed---------Time(h)<BR>\n" );
document.write( "Janet----------------------j------------------<BR>\n" );
document.write( "April----------------------a------------------\r<BR>\n" );
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document.write( "b) set up a system of linear equations ready to enter into your Ti-83 to represent this situation.\r<BR>\n" );
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document.write( "c)Find each of their speeds.\r<BR>\n" );
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document.write( "Please can you do this question and show the work. I tend to understand more when i see the steps that were taken to get the answer. Thank you! : D </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #169455 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=169455\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Janet drove her car due west for 3 hours while April drove her car due east for 2 hours. Janet drove 20km/hr faster than April. Their total distance driven combined is 400 km. <BR>\n" );
document.write( "a) Complete the following table<BR>\n" );
document.write( "Janet DATA:<BR>\n" );
document.write( "time = 3 hrs ; rate = j km/hr ; distance = 3j km<BR>\n" );
document.write( "----------------<BR>\n" );
document.write( "April DATA:<BR>\n" );
document.write( "time = 2 hrs ; rate = a km/hr ; distance = 2a km<BR>\n" );
document.write( "--------------------------------\r<BR>\n" );
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document.write( "b) set up a system of linear equations ready to enter into your Ti-83 to represent this situation. <BR>\n" );
document.write( "Rate equation: j-a = 20<BR>\n" );
document.write( "distance eq:::3j+2a= 400<BR>\n" );
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document.write( "c)Find each of their speeds.<BR>\n" );
document.write( "Multiply thru the rate equation by 3:<BR>\n" );
document.write( "3j-3a = 60<BR>\n" );
document.write( "Subtract that from the distance equation and solve for \"a\":<BR>\n" );
document.write( "5a = 340<BR>\n" );
document.write( "a = 68 km/hr (April's rate)<BR>\n" );
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document.write( "Since j-a = 20, j = 88 km/hr (Janet's rate) <BR>\n" );
document.write( "------------------------------------------------------------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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