document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=228139>Question 228139</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Which three consecutive integers have a product that is 800 times their sum? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #169413 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=169413\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Which three consecutive integers have a product that is 800 times their sum?<BR>\n" );
document.write( "x*(x+1)*(x+2) = 800*(3x+3)<BR>\n" );
document.write( "x^3 + 3x^2 + 2x = 2400x + 2400<BR>\n" );
document.write( "x^3 + 3x^2 - 2398x - 2400 = 0<BR>\n" );
document.write( "x = -1<BR>\n" );
document.write( "Divide by (x+1)<BR>\n" );
document.write( "--> x^2 + 2x - 2400 = 0<BR>\n" );
document.write( "(x + 50)*(x - 48) = 0<BR>\n" );
document.write( "x = 48<BR>\n" );
document.write( "x = -50<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );