document.write( "Question 227974: How do I solve for y? y:3x-y+3=x-6y \n" ); document.write( "
Algebra.Com's Answer #169360 by JenniferTutors(83)\"\" \"About 
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In this equation, you would get y by itself.\r
\n" ); document.write( "\n" ); document.write( "3x-y+3 = x-6y\r
\n" ); document.write( "\n" ); document.write( "Add the \"-y\" to the other side of the equation.\r
\n" ); document.write( "\n" ); document.write( "3x+3 = x-6y+y
\n" ); document.write( "Combine like terms\r
\n" ); document.write( "\n" ); document.write( "3x+3 = x-5y\r
\n" ); document.write( "\n" ); document.write( "Now, make y by itself by subtracting the \"x\" to the other side of the equation.\r
\n" ); document.write( "\n" ); document.write( "3x-x+3 = -5y\r
\n" ); document.write( "\n" ); document.write( "Now combine like terms.\r
\n" ); document.write( "\n" ); document.write( "2x+3 = -5y\r
\n" ); document.write( "\n" ); document.write( "Now, take the \"-5\" and divide it into itself and the other side of the equation. This is what it would look like:\r
\n" ); document.write( "\n" ); document.write( "\"%28-5y%29%2F%28-5y%29\"=\"%282x%29%2F%28-5%29\"\"%283%29%2F%28-5%29\"\r
\n" ); document.write( "\n" ); document.write( "Now, your left with:\r
\n" ); document.write( "\n" ); document.write( "\"y\"=\"%282x%29%2F%28-5%29\"\"%283%29%2F%28-5%29\"
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