document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=227962>Question 227962</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2x-3/x-4=5/x-4 I attempted to solve by cross multiplying. Could you please help me by explaining how to solve for x? The problem is 2x-3 over x-4=5 over x-4.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #169343 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=169343\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x-3/x-4=5/x-4<BR>\n" );
document.write( "Cross multiply<BR>\n" );
document.write( "(2x-3)*(x-4) = 5(x-4)<BR>\n" );
document.write( "Divide by x-4<BR>\n" );
document.write( "2x-3 = 5<BR>\n" );
document.write( "2x = 8<BR>\n" );
document.write( "x = 4<BR>\n" );
document.write( "----------<BR>\n" );
document.write( "The hard way:<BR>\n" );
document.write( "2x^2 - 11x + 12 = 5x-20<BR>\n" );
document.write( "2x^2 - 16x + 32 = 0<BR>\n" );
document.write( "x^2 - 8x + 16 = 0<BR>\n" );
document.write( "(x-4)^2 = 0<BR>\n" );
document.write( "x = 4<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );