document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=227960>Question 227960</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do you solve the equation  -3.2 + q = -12.3 \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #169340 by </B><A HREF=/tutors/aboutme.mpl?userid=JenniferTutors><B>JenniferTutors(83)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JenniferTutors><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JenniferTutors><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=169340\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -3.2 + q = -12.3\r<BR>\n" );
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document.write( "Get \"q\" by itself on one side of the equation. Since \"-3.2\" is already negative, you would add that number to the other side of the equation (on the side with \"-12.3\"). The problem would look like this:\r<BR>\n" );
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document.write( "q = -12.3 + 3.2\r<BR>\n" );
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document.write( "Now, you combine like terms; -12.3 + 3.2<BR>\n" );
document.write( "Remember to keep the negative sign from the higher number (-12.3)\r<BR>\n" );
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document.write( "-12.3 - 3.2 = -9.1\r<BR>\n" );
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document.write( "q = -9.1\r<BR>\n" );
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document.write( "To check answer, plug \"-9.1\" back into the original equation.  </SPAN>\n" );
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