document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=227928>Question 227928</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose the length of a rectanle is 3cm longer than twice the width and that the peimeter is 90cm.  Setup an equation for the perimeter involving only W the width.  solve this equation algebraically to find length and find the width as well? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #169329 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=169329\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=2W+3<BR>\n" );
document.write( "2L+2W=90<BR>\n" );
document.write( "2(2W+3)+2W=90<BR>\n" );
document.write( "4W+6+2W=90<BR>\n" );
document.write( "6W=90-6<BR>\n" );
document.write( "6W=84<BR>\n" );
document.write( "W=84/6<BR>\n" );
document.write( "W=14 ANS. FOR THE WIDTH.<BR>\n" );
document.write( "L=2*14+3=28+3=31 ANS. FOR THE LENGTH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "2*31+2*14=90<BR>\n" );
document.write( "62+28=90<BR>\n" );
document.write( "90=90 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );