document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=227945>Question 227945</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Algebra:how much water must be boiled away to increase the concentration of 300 gallons of salt solution from 2% to 3%? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #169322 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=169322\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .03*300-x=.02(300-x)<BR>\n" );
document.write( "9-x=6-.02x<BR>\n" );
document.write( "-x+.02x=6-9<BR>\n" );
document.write( "-.98x=-3<BR>\n" );
document.write( "x=-3/-.98<BR>\n" );
document.write( "x=3.06 gal.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( ".03*300-3.06=.02(300-3.06)<BR>\n" );
document.write( "9-3.06=6-.02*3,06<BR>\n" );
document.write( "5.94=6-.06<BR>\n" );
document.write( "5.94=5.94<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );