document.write( "Question 3864: If the two-digit integers M and N are positive and have the same digits, but in reverse order, which of the following CANNOT be the sum of M and N ?
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document.write( " (A) 181
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document.write( " (B) 163
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document.write( " (C) 121
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document.write( " (D) 99
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document.write( " (E) 44
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Algebra.Com's Answer #1693 by khwang(438) ![]() You can put this solution on YOUR website! Let M = 10a + b, then N = 10 b+ a,\r \n" ); document.write( "\n" ); document.write( " So M + N = 11 a + 11 b = 11 (a+b) , this means \n" ); document.write( " M + N should be a multiple of 11. \n" ); document.write( " \n" ); document.write( " Note amont these 5 integers \n" ); document.write( " (A) 181 (B) 163 \n" ); document.write( " are not multiple of 11.\r \n" ); document.write( "\n" ); document.write( " Hope you can see by direct view without any calculations.\r \n" ); document.write( "\n" ); document.write( " In fact an ineger is a multiple of 11 if and only if the \n" ); document.write( " difference of the sum of odd digits and the sum even digits is a multiple \n" ); document.write( " of 11 . e.g. 286, 8294,73524.\r \n" ); document.write( "\n" ); document.write( " Kenny \n" ); document.write( " |