document.write( "Question 227852: six stand up comics A,B,C,D,E, and F are set to perform at a single event, order to be determined randomly. Find the probability that C will perform third and D will perform fourth!\r
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document.write( "thanks so much i really need help! \n" );
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Algebra.Com's Answer #169299 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! six stand up comics A,B,C,D,E, and F are set to perform at a single event, order to be determined randomly. Find the probability that C will perform third and D will perform fourth! \n" ); document.write( "----------- \n" ); document.write( "# of ways to succeed = ?: \n" ); document.write( "Perform 1st: 4 choices \n" ); document.write( "Perform 2nd: 3 choices \n" ); document.write( "Perform 3rd: 1 choice \n" ); document.write( "Perform 4th: 1 choice \n" ); document.write( "Perform 5th: 2 choices \n" ); document.write( "Perform 6th: 1 choice \n" ); document.write( "----------------------------- \n" ); document.write( "Number of ways to succeed = 4*3*1*1*2*1 = 24 \n" ); document.write( "============================= \n" ); document.write( "Number of unrestricted orders: 6! = 720 \n" ); document.write( "============================= \n" ); document.write( "Probability that C will be 3rd and D will be 4th = 24/720 = 0,0333,,,' \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |