document.write( "Question 30219: x+y-2z=-1
\n" ); document.write( "2x-y+z=-6
\n" ); document.write( "3x+2y-3z=-3 \n" ); document.write( "
Algebra.Com's Answer #16928 by Fermat(136)\"\" \"About 
You can put this solution on YOUR website!
x+y-2z=-1 ----------(1)
\n" ); document.write( "2x-y+z=-6 ----------(2)
\n" ); document.write( "3x+2y-3z=-3 --------(3)
\n" ); document.write( "from (1), x = -y+2z-1
\n" ); document.write( "substitute for x = -y+2z-1 into (2) and (3),
\n" ); document.write( "2(-y+2z-1) - y + z = -6
\n" ); document.write( "3(-y+2z-1) + 2y - 3z = -3
\n" ); document.write( "multiplying out,
\n" ); document.write( "-2y + 4z - 2 - y + z = -6
\n" ); document.write( "-3y + 6z - 3 + 2y - 3z = -3
\n" ); document.write( "rearranging,
\n" ); document.write( "-3y + 5z = -4 -------(4)
\n" ); document.write( " -y + 3z = 0 -------(5)
\n" ); document.write( "from (5), y = 3z
\n" ); document.write( "substitute for y = 3z into (4),
\n" ); document.write( "-3(3z) + 5z = -4
\n" ); document.write( "-9z + 5z = -4
\n" ); document.write( "-4z = -4
\n" ); document.write( "z = 1
\n" ); document.write( "=====
\n" ); document.write( "y = 3z
\n" ); document.write( "y = 3
\n" ); document.write( "=====
\n" ); document.write( "x = -y+2z-1
\n" ); document.write( "x = -3 + 2 - 1
\n" ); document.write( "x = -2
\n" ); document.write( "======
\n" ); document.write( "Ans: x=-2, y=3, z=1
\n" ); document.write( "=================== \n" ); document.write( "
\n" );