document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=227838>Question 227838</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you help me solve the system?\r<BR>\n" );
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document.write( "x+2y=-12<BR>\n" );
document.write( "y=20-2x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #169264 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=169264\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You can solve this by substitution or elimination.\r<BR>\n" );
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document.write( "I'll use elimination.\r<BR>\n" );
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document.write( "Your equations are:\r<BR>\n" );
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document.write( "x+2y = -12<BR>\n" );
document.write( "y = 20-2x\r<BR>\n" );
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document.write( "Convert these equations into standard form.\r<BR>\n" );
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document.write( "x + 2y = -12 is already in standard form.\r<BR>\n" );
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document.write( "Take y = 20 - 2x\r<BR>\n" );
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document.write( "Add 2x to both sides to get:\r<BR>\n" );
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document.write( "2x + y = 20\r<BR>\n" );
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document.write( "Your two equations are now:\r<BR>\n" );
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document.write( "x + 2y = -12<BR>\n" );
document.write( "2x + y = 20\r<BR>\n" );
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document.write( "Multiply both sides of the first equation by 2 to get:\r<BR>\n" );
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document.write( "2x + 4y = -24<BR>\n" );
document.write( "2x + y = 20\r<BR>\n" );
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document.write( "subtract second equation from first to get:\r<BR>\n" );
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document.write( "3y = -44\r<BR>\n" );
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document.write( "divide both sides of equation by 3 to get:\r<BR>\n" );
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document.write( "y = -44/3\r<BR>\n" );
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document.write( "Replace y with -44/3 in first equation to get:\r<BR>\n" );
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document.write( "x+2y = -12 becomes:<BR>\n" );
document.write( "x + 2*(-44/3) = -12<BR>\n" );
document.write( "which becomes:<BR>\n" );
document.write( "x - 88/3 = -12<BR>\n" );
document.write( "multiply both sides of this equation by 3 to get:<BR>\n" );
document.write( "3x - 88 = -36<BR>\n" );
document.write( "add 88 to both sides of this equation to get:<BR>\n" );
document.write( "3x = 88 - 36 = 52<BR>\n" );
document.write( "divide both sides of this equation by 3 to get:<BR>\n" );
document.write( "x = 52/3\r<BR>\n" );
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document.write( "you have:<BR>\n" );
document.write( "y = -44/3<BR>\n" );
document.write( "x = 52/3\r<BR>\n" );
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document.write( "Replace x and y in both original equations to confirm these answers are good.\r<BR>\n" );
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document.write( "x+2y = -12<BR>\n" );
document.write( "y = 20-2x\r<BR>\n" );
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document.write( "become:\r<BR>\n" );
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document.write( "52/3 + 2*(-44/3) = -12\r<BR>\n" );
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document.write( "-44/3 = 20 - 2*(52/3)\r<BR>\n" );
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document.write( "first equation becomes 52/3 - 88/3 = - 12 which becomes -36/3 = -12 which becomes -12 = -12 which is true so the value for x and y are good.\r<BR>\n" );
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document.write( "second equation becomes -44/3 = 20 - 104/3 = 60/3 - 104/3 = -44/3 which is also true so the value for x and y are good in both equations.\r<BR>\n" );
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document.write( "your answers are:\r<BR>\n" );
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document.write( "y = -44/3\r<BR>\n" );
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document.write( "x = 52/3\r<BR>\n" );
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document.write( " </SPAN>\n" );
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