document.write( "Question 30227: I'm such a dunce with Math that I'm not even sure if my question is an equation. I have the following word problem.\r
\n" ); document.write( "\n" ); document.write( "Rick is 6 years older than Nick. In 4 years he will be twice as old as Nick. In 10 years Nick will be 2/3 Rick's age. How old are each of them?\r
\n" ); document.write( "\n" ); document.write( "By trial and error I solved the problem as 8 & 2. I can present the problem as x = y + 4,
\n" ); document.write( "x + 4 = y + 4 + 4, and
\n" ); document.write( "(x + 10)* 2 = (y + 10)* 3\r
\n" ); document.write( "\n" ); document.write( "Is there a mathmatical way to solve this? \n" ); document.write( "

Algebra.Com's Answer #16925 by Paul(988) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let Rick's age be x
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--(1)\r
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document.write( "2x+20=3y+30 --(2)\r
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document.write( "Multiply equation 1 by 2 then substract equa: 1 by  equa: 2.
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document.write( "4y+16=2x+8
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document.write( "3y+30=2x+20
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document.write( "y-14=-12
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document.write( "y=2\r
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document.write( "Rick's age = 2+6. = 8\r
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document.write( "Hence, RIck is 8 years old and Nick is 2 years old.
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document.write( "Paul.\r
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