document.write( "Question 30227: I'm such a dunce with Math that I'm not even sure if my question is an equation. I have the following word problem.\r
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document.write( "Rick is 6 years older than Nick. In 4 years he will be twice as old as Nick. In 10 years Nick will be 2/3 Rick's age. How old are each of them?\r
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document.write( "By trial and error I solved the problem as 8 & 2. I can present the problem as x = y + 4,
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document.write( "x + 4 = y + 4 + 4, and
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document.write( "(x + 10)* 2 = (y + 10)* 3\r
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document.write( "Is there a mathmatical way to solve this? \n" );
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Algebra.Com's Answer #16924 by Fermat(136)![]() ![]() You can put this solution on YOUR website! Let R represent the age of Rick. \n" ); document.write( "Let N represent the age of Nick. \n" ); document.write( "Rick is 6 years older than Nick: this becomes, \n" ); document.write( "R = N + 6 -----------------------------------------(1) \n" ); document.write( "In 4 years he (Rick) will be twice as old as Nick: this becomes \n" ); document.write( "R+4 = 2*(N+4) ------------------------------------(2) \n" ); document.write( "From (1), substitute for R = N + 6 into (2), giving \n" ); document.write( "N+6 + 4 = 2N + 8 \n" ); document.write( "6+4-8 = 2N - N \n" ); document.write( "N = 2 \n" ); document.write( "===== \n" ); document.write( "R = N+6 \n" ); document.write( "R = 8 \n" ); document.write( "===== \n" ); document.write( "You only really need the two statements. The third one is redundant. But you can use it to check out your answer. \n" ); document.write( "In 10 years Nick will be 2/3 Rick's age: this becomes \n" ); document.write( "N + 10 = (2/3)(R + 10) \n" ); document.write( "2 + 10 =(2/3)(18) \n" ); document.write( "12 = 12 \n" ); document.write( "lhs = rhs - ans checks out :) \n" ); document.write( "========================== \n" ); document.write( " \n" ); document.write( " |