document.write( "Question 227638: How do I find the plotting points and the the y-intercept?
\n" ); document.write( "y=4/3x+2
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Algebra.Com's Answer #169129 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Looking at \"y=%284%2F3%29x%2B2\" we can see that the equation is in slope-intercept form \"y=mx%2Bb\" where the slope is \"m=4%2F3\" and the y-intercept is \"b=2\" \r
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\n" ); document.write( "\n" ); document.write( "Since \"b=2\" this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis\r
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\n" ); document.write( "\n" ); document.write( "So we have one point \r
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\n" ); document.write( "\n" ); document.write( "Now since the slope is comprised of the \"rise\" over the \"run\" this means\r
\n" ); document.write( "\n" ); document.write( "\"slope=rise%2Frun\"\r
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\n" ); document.write( "\n" ); document.write( "Also, because the slope is \"4%2F3\", this means:\r
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\n" ); document.write( "\n" ); document.write( "\"rise%2Frun=4%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "which shows us that the rise is 4 and the run is 3. This means that to go from point to point, we can go up 4 and over 3\r
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\n" ); document.write( "\n" ); document.write( "So starting at , go up 4 units \r
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\n" ); document.write( "\n" ); document.write( "and to the right 3 units to get to the next point \r
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\n" ); document.write( "\n" ); document.write( "Now draw a line through these points to graph \"y=%284%2F3%29x%2B2\"\r
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\n" ); document.write( "\n" ); document.write( " So this is the graph of \"y=%284%2F3%29x%2B2\" through the points and
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