document.write( "Question 227646: \"2log%28%28x%29%29=log%28%28a%29%29-log%28%28b%29%29%2Blog%28%28c%29%29\" \n" ); document.write( "
Algebra.Com's Answer #169097 by drj(1380)\"\" \"About 
You can put this solution on YOUR website!
\"2log%28%28x%29%29=log%28%28a%29%29-log%28%28b%29%29%2Blog%28%28c%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "Step 1. We note that \"2log%28%28x%29%29=log%28%28x%29%29%2Blog%28%28x%29%29=log%28%28x%5E2%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "Step 2. We note that \"log%28%28a%29%29%2Blog%28%28b%29%29%2Blog%28%28c%29%29=log%28%28abc%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "Step 3. Then, \"x%5E2=abc\" after taking the anti-logarithm to both sides of the given equation \"2log%28%28x%29%29=log%28%28a%29%29%2Blog%28%28b%29%29%2Blog%28%28c%29%29\".\r
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\n" ); document.write( "\n" ); document.write( "Step 4. ANSWER: The equation associated with \"2log%28%28x%29%29=log%28%28a%29%29%2Blog%28%28b%29%29%2Blog%28%28c%29%29\" is \"x%5E2=abc\"\r
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\n" ); document.write( "\n" ); document.write( "I hope the above steps and explanation were helpful.\r
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\n" ); document.write( "\n" ); document.write( "For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.\r
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\n" ); document.write( "\n" ); document.write( "And good luck in your studies!\r
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\n" ); document.write( "\n" ); document.write( "Respectfully,
\n" ); document.write( "Dr J\r
\n" ); document.write( "\n" ); document.write( "http://www.FreedomUniversity.TV
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