document.write( "Question 227469: What is the equation of the line in slope-intercept form that passes through (12,0) and is parallel to y=-1/2x-3? \n" ); document.write( "
Algebra.Com's Answer #169019 by nerdybill(7384)\"\" \"About 
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What is the equation of the line in slope-intercept form that passes through (12,0) and is parallel to y=-1/2x-3?
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\n" ); document.write( "For our line to be \"parallel\" to
\n" ); document.write( "y=-1/2x-3
\n" ); document.write( "it MUST have the same slope.
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\n" ); document.write( "Because
\n" ); document.write( "y=-1/2x-3
\n" ); document.write( "is in \"slope-intercept\" form:
\n" ); document.write( "y = mx + b
\n" ); document.write( "where m is the slope
\n" ); document.write( "we see that our new line MUST have a slope of -1/2
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\n" ); document.write( "So, now we know our line must have
\n" ); document.write( "slope (m) = -1/2
\n" ); document.write( "and passes thru (12,0)
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\n" ); document.write( "Plug the above into the \"point-slope\" form:
\n" ); document.write( "y - y1 = m(x - x1)
\n" ); document.write( "y - 0 = (-1/2)(x - 12)
\n" ); document.write( "y - 0 = (-1/2)x + 6
\n" ); document.write( "y = (-1/2)x + 6 (this is what they're looking for)\r
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