document.write( "Question 30129: For two numbers whose sum is q and whose difference is r, write an expression for each number in terms of q and r. \n" ); document.write( "
Algebra.Com's Answer #16897 by sdmmadam@yahoo.com(530)\"\" \"About 
You can put this solution on YOUR website!
For two numbers whose sum is q and whose difference is r, write an expression for each number in terms of q and r.
\n" ); document.write( "Let the numbers be M and N say with M >N
\n" ); document.write( "sum is q and difference is r
\n" ); document.write( "That is M+N = q ----(1)
\n" ); document.write( "and M-N= r ----(2)
\n" ); document.write( "(1)+(2) implies
\n" ); document.write( "(M+M) = (q+r)
\n" ); document.write( "2M = (q+r)
\n" ); document.write( "Therefore M= (q+r)/2 ----(*)
\n" ); document.write( "Putting (*) in (1)
\n" ); document.write( "N = q-M
\n" ); document.write( "=q-(q+r)/2
\n" ); document.write( "=[2q-(q+r)]/2
\n" ); document.write( "=(2q-q-r)/2
\n" ); document.write( "=(q-r)/2
\n" ); document.write( "Answer: The numbers are (q+r)/2 and (q-r)/2
\n" ); document.write( "Verification: Obviously their addition gives q and difference gives r
\n" ); document.write( "Hence our values are correct\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );