document.write( "Question 227284: How many millimeters of pure acid must be added to 120 milliliters of a 30% acid solution to obtain a 50% solution? \n" ); document.write( "
Algebra.Com's Answer #168954 by checkley77(12844)\"\" \"About 
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.30*120+x=.50(120+x)
\n" ); document.write( "36+x=60+.5x
\n" ); document.write( "x-.5x=60-36
\n" ); document.write( ".5x=24
\n" ); document.write( "x=24/.5
\n" ); document.write( "x=48 ml of pure acid is used.
\n" ); document.write( "Proof:
\n" ); document.write( ".30*120+48=.5(120+48)
\n" ); document.write( "36+48=.5*168
\n" ); document.write( "84=84
\n" ); document.write( "
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