document.write( "Question 30200: I would appreciate some help. It has been a while since I have done this. I am to solve the equation: 2/5 + 1/3 t = 5.\r
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Algebra.Com's Answer #16895 by sdmmadam@yahoo.com(530)\"\" \"About 
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Is the problem (2/5) + (1/3) t = 5 ?
\n" ); document.write( "2/5 + (1/3) t = 5. ----(1)
\n" ); document.write( "(1/3)t = 5 -2/5 (subtracting 2/5 from both the sides or shifting 2/5 from the left to the right side to group like terms, changing sign while changing side)
\n" ); document.write( "t/3 =(25-2)/5
\n" ); document.write( "t/3 = 23/5
\n" ); document.write( "Multipllying by 3
\n" ); document.write( "t = (23/5)X3 = 69/5
\n" ); document.write( "Answer: t = 69/5
\n" ); document.write( "Verification: Putting t =69/5 in (1)
\n" ); document.write( "LHS = (2/5)+(1/3)X(69/5)
\n" ); document.write( "=2/5 +23/5
\n" ); document.write( "=(2+23)/5
\n" ); document.write( "=25/5
\n" ); document.write( "=5 = RHS
\n" ); document.write( "Therefore our value is right.
\n" ); document.write( "Note: If the given problem is 2/5 + 1/(3t) = 5. ----(2)
\n" ); document.write( "Then 1/(3t) = 5-2/5
\n" ); document.write( "1/3t = 23/5
\n" ); document.write( "(3t)X(23) = (1)X(5) (cross multiplying)
\n" ); document.write( "[the nr of the left multiplied by the dr of the right = the nr of the right multiplied by the dr of the left]
\n" ); document.write( "69t = 5
\n" ); document.write( "Therefore t = 5/69
\n" ); document.write( "Verification:Putting t =5/69 in (2)
\n" ); document.write( "LHS = (2/5)+ [1/(3X5/69)]
\n" ); document.write( "2/5+23/5 = 25/5 =5 =RHS
\n" ); document.write( "Therefore our value is right
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