document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=227120>Question 227120</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The problem is I completely do not understand<BR>\n" );
document.write( "It states solve using the principle of zero products<BR>\n" );
document.write( "(2x + 2/5)(4x - 1/7)= 0\r<BR>\n" );
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document.write( "Can anyone show me how to do this? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #168887 by </B><A HREF=/tutors/aboutme.mpl?userid=tam67><B>tam67(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tam67><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=168887\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I think I have figured this out I'll try to explain it in detail but please let me know if I'm right or wrong.\r<BR>\n" );
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document.write( "(2x + 2/5)(4x - 1/7)= 0 <BR>\n" );
document.write( "I take the first set of ( ) and set it equal to zero:<BR>\n" );
document.write( "2x + 2/5 = 0<BR>\n" );
document.write( "2x + 2/5 - 2/5 = -2/5<BR>\n" );
document.write( " Then solve for x: The 2 on the left is the same as 2/1, and we can multiply each side by the reciprocal, which is 1/2<BR>\n" );
document.write( "(1/2)2x = -2/5(1/2)<BR>\n" );
document.write( "x = -2/10 =-1/5\r<BR>\n" );
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document.write( "Now I'll plug in -1/5 for x<BR>\n" );
document.write( "(2(-1/5) + 2/5)(4(-1/5) - 1/7)= 0 <BR>\n" );
document.write( "(-2/5 + 2/5)(-4/5 - 1/7)<BR>\n" );
document.write( "0(28/35 -5/35)<BR>\n" );
document.write( "0(23/35)=0\r<BR>\n" );
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document.write( "now the same for the second ( )<BR>\n" );
document.write( "4x - 1/7 = 0<BR>\n" );
document.write( "4x - 1/7 + 1/7 = 1/7<BR>\n" );
document.write( "(1/4)4x = 1/7(1/4)<BR>\n" );
document.write( "x = 1/28\r<BR>\n" );
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document.write( "Now I plug in 1/28 for x<BR>\n" );
document.write( "(2(1/28) + 2/5)(4(1/28) - 1/7)= 0<BR>\n" );
document.write( "(2/28 + 2/5)(4/28 - 1/7)<BR>\n" );
document.write( "(10/140 + 56/140)(20/140 - 20/140)<BR>\n" );
document.write( "66/140(0) = 0\r<BR>\n" );
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document.write( "Please let me know how I done\r<BR>\n" );
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document.write( " </SPAN>\n" );
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