document.write( "Question 227118: Where is the center of the circle given by the equation (x + 7)2 + (y - 5)2 = 16? \n" ); document.write( "
Algebra.Com's Answer #168864 by Theo(13342)\"\" \"About 
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This looks like the vertex form of the equation for a circle.\r
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\n" ); document.write( "\n" ); document.write( "The general form of that should be:\r
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\n" ); document.write( "\n" ); document.write( "(x-h)^2 + (y-k)^2 = r^2\r
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\n" ); document.write( "\n" ); document.write( "where:\r
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\n" ); document.write( "\n" ); document.write( "(h,k) is the (x,y) coordinates of the center of the circle.\r
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\n" ); document.write( "\n" ); document.write( "Since -h = +7, then h must be -7.\r
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\n" ); document.write( "\n" ); document.write( "Since -k = -5, then k must be 5.\r
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\n" ); document.write( "\n" ); document.write( "Center of your circle is at x,y) = (-7,5)\r
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\n" ); document.write( "\n" ); document.write( "To graph your circle, we need to solve for y.\r
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\n" ); document.write( "\n" ); document.write( "Your equation is:\r
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\n" ); document.write( "\n" ); document.write( "(x + 7)^2 + (y - 5)^2 = 16\r
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\n" ); document.write( "\n" ); document.write( "Subtract (x+7)^2 from both sides to get:\r
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\n" ); document.write( "\n" ); document.write( "(y-5)^2 = 16 - (x+7)^2)\r
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\n" ); document.write( "\n" ); document.write( "Take the square root of both sides of the equation to get:\r
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\n" ); document.write( "\n" ); document.write( "y-5 = +/- \"sqrt%2816-%28x%2B7%29%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Add 5 to both sides of the equation to get:\r
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\n" ); document.write( "\n" ); document.write( "y = 5 +/- \"sqrt%2816-%28x%2B7%29%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "graph of your equation looks like.....\r
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