document.write( "Question 227103: Please help multiply and simplify\r
\n" ); document.write( "\n" ); document.write( "(25c^2/3c^2-18c+27) * (3c-9/5c) = ?
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Algebra.Com's Answer #168850 by algebrapro18(249)\"\" \"About 
You can put this solution on YOUR website!
Well first we need to factor these expressions as much as possible.
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\n" ); document.write( "\n" ); document.write( "25c^2 = 5c(5c)
\n" ); document.write( "3c^2-18c+27 = 3(c^2-6c+9) = 3(c-3)(c-3)
\n" ); document.write( "3c-9 = 3(c-3)
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\n" ); document.write( "\n" ); document.write( "so plugging back in we get:
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\n" ); document.write( "\n" ); document.write( "(25c^2/3c^2-18c+27) * (3c-9/5c) = 5c(5c)/3(c-3)(c-3) * 3(c-3)/5c
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\n" ); document.write( "\n" ); document.write( "Now we simplify as much as we can before we multiply.
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\n" ); document.write( "\n" ); document.write( "the 5c on top can cross with the 5c on bottom. The 3(c-3) on the bottom can cross with the 3(c-3) on the top.
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\n" ); document.write( "\n" ); document.write( "This will leave us with the final answer of \"5c%2F%28c-3%29\"
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