document.write( "Question 227094: John's age is 2 years, less than three times Paul his son,s age. His son Mark is
\n" ); document.write( "15 years older than Paul. The sum of their ages is 103. Find the ages of John and histwo sons.
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Algebra.Com's Answer #168847 by drj(1380)\"\" \"About 
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John's age is 2 years less than three times Paul his son's age. His son Mark is
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\n" ); document.write( "\n" ); document.write( "Step 1. Let x be the age of Paul.\r
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\n" ); document.write( "\n" ); document.write( "Step 2. Let x+15 be the age of Mark since Mark is 15 years older than Paul.\r
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\n" ); document.write( "\n" ); document.write( "Step 3. Let 3x-2 be the age of John since John is 2 years les than 3 times Paul his son's age.\r
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\n" ); document.write( "\n" ); document.write( "Step 4. Then, \"x%2Bx%2B15%2B3x-2=103\" or \"5x%2B13=103\" since the sum of their sages is 103.\r
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\n" ); document.write( "\n" ); document.write( "Step 5. Solving yields the following steps for the equation \"5x%2B13=103\"\r
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\n" ); document.write( "\n" ); document.write( "Subtract 13 from both sides of the equation\r
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\n" ); document.write( "\n" ); document.write( "\"5x%2B13-13=103-13\"\r
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\n" ); document.write( "\n" ); document.write( "\"5x=90\"\r
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\n" ); document.write( "\n" ); document.write( "Divide by 5 to both sides of the equation\r
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\n" ); document.write( "\n" ); document.write( "\"5x=90\"\r
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\n" ); document.write( "\n" ); document.write( "\"5x%2F5=90%2F5\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=18\", Then \"3x-2=52\" and \"x%2B15=33\"\r
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\n" ); document.write( "\n" ); document.write( "Check sum of ages: \"18%2B52%2B33=103\" which is a true statement.\r
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\n" ); document.write( "\n" ); document.write( "Step 6. ANSWER: John is 52 years old, Mark is 33 years old, and Paul is 18 years old.\r
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\n" ); document.write( "\n" ); document.write( "I hope the above steps were helpful.\r
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\n" ); document.write( "\n" ); document.write( "For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.\r
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\n" ); document.write( "\n" ); document.write( "And good luck in your studies!\r
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\n" ); document.write( "\n" ); document.write( "Respectfully,
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\n" ); document.write( "\n" ); document.write( "http://www.FreedomUniversity.TV\r
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