document.write( "Question 227094: John's age is 2 years, less than three times Paul his son,s age. His son Mark is
\n" ); document.write( "15 years older than Paul. The sum of their ages is 103. Find the ages of John and histwo sons. \n" ); document.write( "

Algebra.Com's Answer #168846 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"j\"$ = John's age now
\n" ); document.write( "Let $\"m\"$ = Mark's age now
\n" ); document.write( "Let $\"p\"$ = Paul's age now
\n" ); document.write( "given:
\n" ); document.write( "(1) $\"j+=+3p+-+2\"$
\n" ); document.write( "(2) $\"m+=+p+%2B+15\"$
\n" ); document.write( "(3) $\"j+%2B+p+%2B+m+=+103\"$
\n" ); document.write( "Substitute (1) and (2) into (3)
\n" ); document.write( "(3) $\"j+%2B+p+%2B+m+=+103\"$
\n" ); document.write( " $\"3p+-+2+%2B+p+%2B+p+%2B+15+=+103\"$
\n" ); document.write( " $\"5p+%2B+13+=+103\"$
\n" ); document.write( " $\"5p+=+90\"$
\n" ); document.write( " $\"p+=+18\"$
\n" ); document.write( "and, from (1)
\n" ); document.write( "(1) $\"j+=+3p+-+2\"$
\n" ); document.write( " $\"j+=+3%2A18+-+2\"$
\n" ); document.write( " $\"j+=+54+-+2\"$
\n" ); document.write( " $\"j+=+52\"$
\n" ); document.write( "and, from (2)
\n" ); document.write( "(2) $\"m+=+p+%2B+15\"$
\n" ); document.write( " $\"m+=+18+%2B+15\"$
\n" ); document.write( " $\"m+=+33\"$
\n" ); document.write( "John is 52, Paul is 18, Mark is 33
\n" ); document.write( "check:
\n" ); document.write( "(3) $\"j+%2B+p+%2B+m+=+103\"$
\n" ); document.write( " $\"52+%2B+18+%2B+33+=+103\"$
\n" ); document.write( " $\"103+=+103\"$
\n" ); document.write( "OK\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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