document.write( "Question 226802: carl and candice leave the same point riding bikes in the same direction. Candice rides at 3/4 carl's speed. After 2 hours, they are 28 miles apart. what is the average speed of each rider?
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Algebra.Com's Answer #168828 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! carl and candice leave the same point riding bikes in the same direction. \n" ); document.write( " Candice rides at 3/4 carl's speed. \n" ); document.write( " After 2 hours, they are 28 miles apart. \n" ); document.write( "what is the average speed of each rider? \n" ); document.write( ": \n" ); document.write( "Let s = Carl's speed \n" ); document.write( "then \n" ); document.write( ".75s = Candice's speed \n" ); document.write( ": \n" ); document.write( "Write a distance equation; (Dist = speed * time) \n" ); document.write( ": \n" ); document.write( "Carl's dist - Candice's dist = 28 miles \n" ); document.write( "2s - 2(.75s) = 28 \n" ); document.write( "2s - 1.5s = 28 \n" ); document.write( ".5s = 28 \n" ); document.write( "s = \n" ); document.write( "s = 56 mph, Carl's speed \n" ); document.write( "then \n" ); document.write( ".75(56) = 42 mph is Candice's speed \n" ); document.write( "; \n" ); document.write( "; \n" ); document.write( "Check this by finding the distance each traveled. \n" ); document.write( "2*56 = 112 mi \n" ); document.write( "2*42 = 84 mi \n" ); document.write( "-------------- \n" ); document.write( "differ= 28 mi \n" ); document.write( " \n" ); document.write( " |