document.write( "Question 30152: Question:
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document.write( "x^2+5x>24\r
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document.write( "Possible Answers:
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document.write( "a. none of these
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document.write( "b. -3
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document.write( "d. X<-8 or x>3
Algebra.Com's Answer #16881 by sdmmadam@yahoo.com(530)![]() ![]() ![]() You can put this solution on YOUR website! x^2+5x>24 \n" ); document.write( "That is x^2+5x-24 > 0 \n" ); document.write( "(x+8)(x-3) > 0 \n" ); document.write( "Since either positive multiplied by positive is positive OR \n" ); document.write( "negative multiplied by negative is positive, there are two cases. \n" ); document.write( "Case 1: Let (x+8) > 0 together with (x-3) > 0 \n" ); document.write( "This implies x > -8 together with x > 3 \n" ); document.write( "And since anything to the right of 3 is definitely to the right of (-8), \n" ); document.write( "the verdict for this case is \n" ); document.write( "x > 3 \n" ); document.write( "Case 2: Let (x+8) < 0 together with (x-3) < 0 \n" ); document.write( "This implies x < -8 together with x < 3 \n" ); document.write( "And since anything to the left of (-8) is definitely to the left of 3, \n" ); document.write( "the verdict for this case is \n" ); document.write( "x < -8 \n" ); document.write( "Therefore combining the results of both the cases we have \n" ); document.write( "Answer: x< -8 and x > 3 \n" ); document.write( "Which is your choice (d) \n" ); document.write( "Note: (factoring the quadratic expression: x^2+5x-24, \n" ); document.write( "product =(-24) and sum is 5 and therefore the quantities are (+8) and (-5) \n" ); document.write( "and therefore x^2+5x-24 \n" ); document.write( "= x^2+(8x-3x)-24 \n" ); document.write( "= (x^2+8x)-3x-24 \n" ); document.write( "=x(x+8)-3(x+8) \n" ); document.write( "=xp-3p where p = (x+8) \n" ); document.write( "=p(x-3) \n" ); document.write( "=(x+8)(x-3)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |