document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=226913>Question 226913</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given that the area of an equilateral triangle is 57 cm^2, find its perimeter. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #168798 by </B><A HREF=/tutors/aboutme.mpl?userid=anantha><B>anantha(86)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=anantha><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=168798\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sol:<BR>\n" );
document.write( "Area of an equilateral triangle=squareroot(3)/4*a^2<BR>\n" );
document.write( "inthe above formula a is side of an equilateral triangle<BR>\n" );
document.write( "according to the question area of an equilateral triangle=57 cm^2<BR>\n" );
document.write( "squareroot(3)/4*a^2=57<BR>\n" );
document.write( "multiplying both sides by 4/root(3)<BR>\n" );
document.write( "root(3)/4*4/root(3)*a^2=57*4/1.732   (root(3)=1.732)<BR>\n" );
document.write( "after cancilation<BR>\n" );
document.write( "a^2=228/1.732<BR>\n" );
document.write( "a^2=131.63<BR>\n" );
document.write( "a=root(131.63)<BR>\n" );
document.write( "a=11.47<BR>\n" );
document.write( "now the perimeter of equilateral triangle=root(3)/2*a<BR>\n" );
document.write( "=1.732/2*(11.47)<BR>\n" );
document.write( "=0.866*11.47<BR>\n" );
document.write( "=9.93cm<BR>\n" );
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