document.write( "Question 226867: Hi i need help solving these equations: the square root of (2r squared - 121)= r\r
\n" ); document.write( "\n" ); document.write( "and : 4+ square root of (m-2)=m
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Algebra.Com's Answer #168792 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
\"sqrt%282r%5E2+-+121%29\" = r
\n" ); document.write( "Square both sides and you have
\n" ); document.write( "2r^2 - 121 = r^2
\n" ); document.write( "2r^2 - r^2 = + 121
\n" ); document.write( "r^2 = 121
\n" ); document.write( "r = \"sqrt%28121%29\"
\n" ); document.write( "r = +11 is the valid solution
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\n" ); document.write( "\"4+%2B+sqrt%28m-2%29\" = m
\n" ); document.write( "\"sqrt%28m-2%29\" = m - 4
\n" ); document.write( "Square both sides
\n" ); document.write( " m - 2 = (m-4)^2
\n" ); document.write( "m - 2 = m^2 - 8m + 16
\n" ); document.write( "0 = m^2 - 8m - m + 16 + 2
\n" ); document.write( "A quadratic equation
\n" ); document.write( "m^2 - 9m + 18
\n" ); document.write( "Factors to
\n" ); document.write( "(m-6)(m-3) = 0
\n" ); document.write( "m = 6
\n" ); document.write( "and
\n" ); document.write( "m = 3
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\n" ); document.write( "You check both solutions in original equation, only one is valid
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