document.write( "Question 226682: I need help with figuring out how to do a problem like this: \r \n" );
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document.write( "Solve the following systems of equations using any method. Check each solution, if possible: \n" );
document.write( "a. -2x+3y=1 \n" );
document.write( " 2x+6y=2 \n" );
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document.write( "solution: \n" );
document.write( "Solve the second equation for x \n" );
document.write( " (you could solve for y - it \n" );
document.write( " doesn't matter). \n" );
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document.write( " 2x + 6 y = 2 becomes x = -3y +1 \n" );
document.write( " Now, substitute -3y +1 \n" );
document.write( " for x in the first equation. This gives \n" );
document.write( " the equation -2(-3y +1)+3y = 1 \n" );
document.write( " 6y -2 +3y =1 \n" );
document.write( " 9y -2 =1 \n" );
document.write( " 9y= 3 \n" );
document.write( " y=3/9 or y = 1/3 \n" );
document.write( " Now, substitute 1/3 for y in \n" );
document.write( " either equation and solve for x. \n" );
document.write( " (We use the second equation below.) \n" );
document.write( " 2x + 6(1/3) = 2 \n" );
document.write( " 2x + 2 = 2 \n" );
document.write( " 2x = 2- 2 \n" );
document.write( " 2x =0 , x = 0 \n" );
document.write( " The solution is the ordered pair, \n" );
document.write( " (0, 1/3). \n" );
document.write( " now you can check where you see x just replace with 0 , and where see y just replace it with (1/3)..\r \n" );
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document.write( "good luck\r \n" );
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